56. Merge Intervals

56. Merge Intervals

题目

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  public int[][] merge(int[][] a) {
//1. 先去除a为空的情况
if(a.length==0)return new int[][]{};
Integer[][] intervals = new Integer[a.length][a[0].length];
//2. 为了方便排序,将其转换为Integer数组
cpy(a, intervals);

//3. 排序
Arrays.sort(intervals, new Comparator<Integer[]>() {

@Override
public int compare(Integer[] x, Integer[] y) {
if(x[0] < y[0]){
return -1;
} else if(x[0] > y[0]){
return 1;
} else {
return 0;
}
}

});
//4. 遍历查找是否相交
ArrayList<Integer[]> list = new ArrayList<>();
for(int i=0;i<intervals.length;i++) {
int j = i;
Integer[] tIntegers = new Integer[2];
tIntegers[0] = intervals[i][0];
tIntegers[1] = intervals[i][1];
//有相交的情况
while(i+1<=intervals.length-1&&intervals[i+1][0]<=tIntegers[1]) {
if(intervals[i+1][1]>tIntegers[1]) {
tIntegers[1] = intervals[i+1][1];
}
i++;
}

list.add(tIntegers);
}
//5. 转换为int[][]返回
int[][] res = new int[list.size()][2];
for(int i=0;i<list.size();i++) {
Integer[] integers = list.get(i);
res[i][0] = integers[0];
res[i][1] = integers[1];
}
return res;
}

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